Search a number
-
+
120003301330111 = 313333382989667
BaseRepresentation
bin11011010010010001110010…
…001001011100110010111111
3120201220012111101210222111001
4123102101302021130302333
5111212113230120030421
61103120431111511131
734163644451056243
oct3322216211346277
9521805441728431
10120003301330111
1135267129137401
121156153a9884a7
1351c6355386544
14218c2956b4423
15dd18643bc691
hex6d247225ccbf

120003301330111 has 4 divisors (see below), whose sum is σ = 120003684633112. Its totient is φ = 120002918027112.

The previous prime is 120003301330061. The next prime is 120003301330169. The reversal of 120003301330111 is 111033103300021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120003301330111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120003301330811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191181501 + ... + 191808166.

It is an arithmetic number, because the mean of its divisors is an integer number (30000921158278).

Almost surely, 2120003301330111 is an apocalyptic number.

120003301330111 is a deficient number, since it is larger than the sum of its proper divisors (383303001).

120003301330111 is an equidigital number, since it uses as much as digits as its factorization.

120003301330111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383303000.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 120003301330111 its reverse (111033103300021), we get a palindrome (231036404630132).

The spelling of 120003301330111 in words is "one hundred twenty trillion, three billion, three hundred one million, three hundred thirty thousand, one hundred eleven".

Divisors: 1 313333 382989667 120003301330111