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1200040023 = 37134395751
BaseRepresentation
bin100011110000111…
…0010100001010111
310002122002100102210
41013201302201113
54424202240043
6315025004503
741511112650
oct10741624127
93078070383
101200040023
11566433916
12295a83733
13161809770
14b5540527
1570547633
hex47872857

1200040023 has 16 divisors (see below), whose sum is σ = 1969296896. Its totient is φ = 632988000.

The previous prime is 1200040003. The next prime is 1200040031. The reversal of 1200040023 is 3200400021.

It is not a de Polignac number, because 1200040023 - 25 = 1200039991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200039990 and 1200040008.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200040003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2197603 + ... + 2198148.

It is an arithmetic number, because the mean of its divisors is an integer number (123081056).

Almost surely, 21200040023 is an apocalyptic number.

1200040023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1200040023 is a deficient number, since it is larger than the sum of its proper divisors (769256873).

1200040023 is a wasteful number, since it uses less digits than its factorization.

1200040023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4395774.

The product of its (nonzero) digits is 48, while the sum is 12.

The square root of 1200040023 is about 34641.5938288064. The cubic root of 1200040023 is about 1062.6703831579.

Adding to 1200040023 its reverse (3200400021), we get a palindrome (4400440044).

The spelling of 1200040023 in words is "one billion, two hundred million, forty thousand, twenty-three".

Divisors: 1 3 7 13 21 39 91 273 4395751 13187253 30770257 57144763 92310771 171434289 400013341 1200040023