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1200040043314 = 2785717145951
BaseRepresentation
bin10001011101100111111…
…101011110001100110010
311020201111212001112002011
4101131213331132030302
5124130140222341224
62315142450513134
7152462053031260
oct21354775361462
94221455045064
101200040043314
11422a30357242
121746aab957aa
1389217998188
144212198d430
152133849a394
hex11767f5e332

1200040043314 has 8 divisors (see below), whose sum is σ = 2057211502848. Its totient is φ = 514302875700.

The previous prime is 1200040043303. The next prime is 1200040043317. The reversal of 1200040043314 is 4133400400021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×12000400433142 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1200040043317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42858572962 + ... + 42858572989.

It is an arithmetic number, because the mean of its divisors is an integer number (257151437856).

Almost surely, 21200040043314 is an apocalyptic number.

1200040043314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1200040043314 is a deficient number, since it is larger than the sum of its proper divisors (857171459534).

1200040043314 is an equidigital number, since it uses as much as digits as its factorization.

1200040043314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85717145960.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1200040043314 its reverse (4133400400021), we get a palindrome (5333440443335).

The spelling of 1200040043314 in words is "one trillion, two hundred billion, forty million, forty-three thousand, three hundred fourteen".

Divisors: 1 2 7 14 85717145951 171434291902 600020021657 1200040043314