1200101001113 has 4 divisors (see below), whose sum is σ = 1371544001280. Its totient is φ = 1028658000948.

The previous prime is 1200101001109. The next prime is 1200101001119. The reversal of 1200101001113 is 3111001010021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200101001113 - 2² = 1200101001109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200101001094 and 1200101001103.

It is not an unprimeable number, because it can be changed into a prime (1200101001119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85721500073 + ... + 85721500086.

It is an arithmetic number, because the mean of its divisors is an integer number (342886000320).

Almost surely, 2^{1200101001113} is an apocalyptic number.

It is an amenable number.

1200101001113 is a deficient number, since it is larger than the sum of its proper divisors (171443000167).

1200101001113 is an equidigital number, since it uses as much as digits as its factorization.

1200101001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171443000166.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 1200101001113 its reverse (3111001010021), we get a palindrome (4311102011134).

The spelling of 1200101001113 in words is "one trillion, two hundred billion, one hundred one million, one thousand, one hundred thirteen".