Base | Representation |
---|---|
bin | 11011010010011000100111… |
… | …001101110111010011010011 |
3 | 120201220220102102202211202221 |
4 | 123102120213031313103103 |
5 | 111212223234314140033 |
6 | 1103124042455121511 |
7 | 34164324250616404 |
oct | 3322304715672323 |
9 | 521826372684687 |
10 | 120010634130643 |
11 | 3526a251328a33 |
12 | 11562a46673297 |
13 | 51c6c53602b79 |
14 | 218c78d5019ab |
15 | dd1b4302412d |
hex | 6d26273774d3 |
120010634130643 has 4 divisors (see below), whose sum is σ = 120011085254448. Its totient is φ = 120010183006840.
The previous prime is 120010634130641. The next prime is 120010634130683. The reversal of 120010634130643 is 346031436010021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120010634130643 - 21 = 120010634130641 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120010634130599 and 120010634130608.
It is not an unprimeable number, because it can be changed into a prime (120010634130641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225162628 + ... + 225694993.
It is an arithmetic number, because the mean of its divisors is an integer number (30002771313612).
Almost surely, 2120010634130643 is an apocalyptic number.
120010634130643 is a deficient number, since it is larger than the sum of its proper divisors (451123805).
120010634130643 is an equidigital number, since it uses as much as digits as its factorization.
120010634130643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 451123804.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 120010634130643 in words is "one hundred twenty trillion, ten billion, six hundred thirty-four million, one hundred thirty thousand, six hundred forty-three".
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