120011002222001 has 4 divisors (see below), whose sum is σ = 130921093333104. Its totient is φ = 109100911110900.

The previous prime is 120011002221983. The next prime is 120011002222009. The reversal of 120011002222001 is 100222200110021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120011002222001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120011002222009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5455045555535 + ... + 5455045555556.

It is an arithmetic number, because the mean of its divisors is an integer number (32730273333276).

Almost surely, 2^{120011002222001} is an apocalyptic number.

120011002222001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

120011002222001 is a deficient number, since it is larger than the sum of its proper divisors (10910091111103).

120011002222001 is a wasteful number, since it uses less digits than its factorization.

120011002222001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10910091111102.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 120011002222001 its reverse (100222200110021), we get a palindrome (220233202332022).

The spelling of 120011002222001 in words is "one hundred twenty trillion, eleven billion, two million, two hundred twenty-two thousand, one".