120011333212033 has 4 divisors (see below), whose sum is σ = 120327985806640. Its totient is φ = 119694680617428.

The previous prime is 120011333212007. The next prime is 120011333212091. The reversal of 120011333212033 is 330212333110021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120011333212033 is a prime.

It is a super-2 number, since 2×120011333212033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120011333211989 and 120011333212007.

It is not an unprimeable number, because it can be changed into a prime (120011333212933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158326296735 + ... + 158326297492.

It is an arithmetic number, because the mean of its divisors is an integer number (30081996451660).

Almost surely, 2^{120011333212033} is an apocalyptic number.

It is an amenable number.

120011333212033 is a deficient number, since it is larger than the sum of its proper divisors (316652594607).

120011333212033 is an equidigital number, since it uses as much as digits as its factorization.

120011333212033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 316652594606.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 120011333212033 its reverse (330212333110021), we get a palindrome (450223666322054).

The spelling of 120011333212033 in words is "one hundred twenty trillion, eleven billion, three hundred thirty-three million, two hundred twelve thousand, thirty-three".