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1200122000131 = 2352179217397
BaseRepresentation
bin10001011101101100110…
…110000111001100000011
311020201201120021100200211
4101131230312013030003
5124130322213001011
62315154535254551
7152464066454365
oct21355466071403
94221646240624
101200122000131
11422a7264464a
1217471251a457
138922b962132
144212c804d35
1521340788b21
hex1176cd87303

1200122000131 has 4 divisors (see below), whose sum is σ = 1252301217552. Its totient is φ = 1147942782712.

The previous prime is 1200122000093. The next prime is 1200122000167. The reversal of 1200122000131 is 1310002210021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1200122000131 - 231 = 1197974516483 is a prime.

It is a super-2 number, since 2×12001220001312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1200122000431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26089608676 + ... + 26089608721.

It is an arithmetic number, because the mean of its divisors is an integer number (313075304388).

Almost surely, 21200122000131 is an apocalyptic number.

1200122000131 is a deficient number, since it is larger than the sum of its proper divisors (52179217421).

1200122000131 is an equidigital number, since it uses as much as digits as its factorization.

1200122000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52179217420.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1200122000131 its reverse (1310002210021), we get a palindrome (2510124210152).

The spelling of 1200122000131 in words is "one trillion, two hundred billion, one hundred twenty-two million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 23 52179217397 1200122000131