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1200130003333 = 1779788577017
BaseRepresentation
bin10001011101101101010…
…100101001000110000101
311020201202010022222000201
4101131231110221012011
5124130331240101313
62315155423010501
7152464224466342
oct21355524510605
94221663288021
101200130003333
11422a77110568
12174715139a31
1389230504b61
144212d8c97c9
152134131a0dd
hex1176d529185

1200130003333 has 8 divisors (see below), whose sum is σ = 1272320286552. Its totient is φ = 1128116875776.

The previous prime is 1200130003313. The next prime is 1200130003403. The reversal of 1200130003333 is 3333000310021.

It can be written as a sum of positive squares in 4 ways, for example, as 445285286209 + 754844717124 = 667297^2 + 868818^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200130003333 is a prime.

It is a super-2 number, since 2×12001300033332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1200130003333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200130003313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44274960 + ... + 44302057.

It is an arithmetic number, because the mean of its divisors is an integer number (159040035819).

Almost surely, 21200130003333 is an apocalyptic number.

It is an amenable number.

1200130003333 is a deficient number, since it is larger than the sum of its proper divisors (72190283219).

1200130003333 is an equidigital number, since it uses as much as digits as its factorization.

1200130003333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88577831.

The product of its (nonzero) digits is 486, while the sum is 19.

Adding to 1200130003333 its reverse (3333000310021), we get a palindrome (4533130313354).

The spelling of 1200130003333 in words is "one trillion, two hundred billion, one hundred thirty million, three thousand, three hundred thirty-three".

Divisors: 1 17 797 13549 88577017 1505809289 70595882549 1200130003333