Base | Representation |
---|---|
bin | 10001011101101101010… |
… | …101011101111111110111 |
3 | 11020201202010201222021021 |
4 | 101131231111131333313 |
5 | 124130331314020043 |
6 | 2315155431402011 |
7 | 152464226361160 |
oct | 21355525357767 |
9 | 4221663658237 |
10 | 1200130220023 |
11 | 422a77249349 |
12 | 174715223307 |
13 | 8923057c687 |
14 | 4212d944767 |
15 | 2134135e3ed |
hex | 1176d55dff7 |
1200130220023 has 4 divisors (see below), whose sum is σ = 1371577394320. Its totient is φ = 1028683045728.
The previous prime is 1200130220017. The next prime is 1200130220057. The reversal of 1200130220023 is 3200220310021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1200130220023 - 217 = 1200130088951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200130219979 and 1200130220006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200130226023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85723587138 + ... + 85723587151.
It is an arithmetic number, because the mean of its divisors is an integer number (342894348580).
Almost surely, 21200130220023 is an apocalyptic number.
1200130220023 is a deficient number, since it is larger than the sum of its proper divisors (171447174297).
1200130220023 is an equidigital number, since it uses as much as digits as its factorization.
1200130220023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171447174296.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 1200130220023 its reverse (3200220310021), we get a palindrome (4400350530044).
The spelling of 1200130220023 in words is "one trillion, two hundred billion, one hundred thirty million, two hundred twenty thousand, twenty-three".
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