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1200132300021 = 3400044100007
BaseRepresentation
bin10001011101101101011…
…101011001110011110101
311020201202021122122111020
4101131231131121303311
5124130332332100041
62315155544131353
7152464253143254
oct21355535316365
94221667578436
101200132300021
11422a7843a056
12174715a66b59
1389230b2a345
144212dd2679b
1521341620866
hex1176d759cf5

1200132300021 has 4 divisors (see below), whose sum is σ = 1600176400032. Its totient is φ = 800088200012.

The previous prime is 1200132300013. The next prime is 1200132300047. The reversal of 1200132300021 is 1200032310021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200132300021 - 23 = 1200132300013 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200132300011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200022050001 + ... + 200022050006.

It is an arithmetic number, because the mean of its divisors is an integer number (400044100008).

Almost surely, 21200132300021 is an apocalyptic number.

It is an amenable number.

1200132300021 is a deficient number, since it is larger than the sum of its proper divisors (400044100011).

1200132300021 is an equidigital number, since it uses as much as digits as its factorization.

1200132300021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400044100010.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1200132300021 its reverse (1200032310021), we get a palindrome (2400164610042).

The spelling of 1200132300021 in words is "one trillion, two hundred billion, one hundred thirty-two million, three hundred thousand, twenty-one".

Divisors: 1 3 400044100007 1200132300021