Base | Representation |
---|---|
bin | 10001011101101101111… |
… | …011111010111100000011 |
3 | 11020201202211201002110001 |
4 | 101131231323322330003 |
5 | 124130341404100120 |
6 | 2315200431420431 |
7 | 152464411143025 |
oct | 21355573727403 |
9 | 4221684632401 |
10 | 1200140300035 |
11 | 422a81a03636 |
12 | 174718684717 |
13 | 8923269b791 |
14 | 4213100a015 |
15 | 213421a0e0a |
hex | 1176defaf03 |
1200140300035 has 32 divisors (see below), whose sum is σ = 1540043487360. Its totient is φ = 895616409600.
The previous prime is 1200140300017. The next prime is 1200140300111. The reversal of 1200140300035 is 5300030410021.
It is not a de Polignac number, because 1200140300035 - 27 = 1200140299907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200140299985 and 1200140300021.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12252655 + ... + 12350215.
It is an arithmetic number, because the mean of its divisors is an integer number (48126358980).
Almost surely, 21200140300035 is an apocalyptic number.
1200140300035 is a deficient number, since it is larger than the sum of its proper divisors (339903187325).
1200140300035 is a wasteful number, since it uses less digits than its factorization.
1200140300035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100239.
The product of its (nonzero) digits is 360, while the sum is 19.
Adding to 1200140300035 its reverse (5300030410021), we get a palindrome (6500170710056).
It can be divided in two parts, 1200140 and 300035, that multiplied together give a square (360084004900 = 6000702).
The spelling of 1200140300035 in words is "one trillion, two hundred billion, one hundred forty million, three hundred thousand, thirty-five".
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