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1200140300041 = 9471267307603
BaseRepresentation
bin10001011101101101111…
…011111010111100001001
311020201202211201002110021
4101131231323322330021
5124130341404100131
62315200431420441
7152464411143034
oct21355573727411
94221684632407
101200140300041
11422a81a03641
12174718684721
138923269b797
144213100a01b
15213421a0e11
hex1176defaf09

1200140300041 has 4 divisors (see below), whose sum is σ = 1201407608592. Its totient is φ = 1198872991492.

The previous prime is 1200140300017. The next prime is 1200140300111. The reversal of 1200140300041 is 1400030410021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200140300041 - 213 = 1200140291849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200140299988 and 1200140300024.

It is not an unprimeable number, because it can be changed into a prime (1200140300011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 633652855 + ... + 633654748.

It is an arithmetic number, because the mean of its divisors is an integer number (300351902148).

Almost surely, 21200140300041 is an apocalyptic number.

It is an amenable number.

1200140300041 is a deficient number, since it is larger than the sum of its proper divisors (1267308551).

1200140300041 is an equidigital number, since it uses as much as digits as its factorization.

1200140300041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1267308550.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1200140300041 its reverse (1400030410021), we get a palindrome (2600170710062).

The spelling of 1200140300041 in words is "one trillion, two hundred billion, one hundred forty million, three hundred thousand, forty-one".

Divisors: 1 947 1267307603 1200140300041