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1200143414155 = 5734289811833
BaseRepresentation
bin10001011101101110000…
…111110011001110001011
311020201210001120022012211
4101131232013303032023
5124130343203223110
62315201022245551
7152464446463060
oct21355607631613
94221701508184
101200143414155
11422a83740294
121747197268b7
138923321c05a
14421315bac67
15213425b898a
hex1176e1f338b

1200143414155 has 8 divisors (see below), whose sum is σ = 1645910968032. Its totient is φ = 822955483968.

The previous prime is 1200143414147. The next prime is 1200143414209. The reversal of 1200143414155 is 5514143410021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1200143414155 - 23 = 1200143414147 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17144905882 + ... + 17144905951.

It is an arithmetic number, because the mean of its divisors is an integer number (205738871004).

Almost surely, 21200143414155 is an apocalyptic number.

1200143414155 is a deficient number, since it is larger than the sum of its proper divisors (445767553877).

1200143414155 is an equidigital number, since it uses as much as digits as its factorization.

1200143414155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34289811845.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 1200143414155 its reverse (5514143410021), we get a palindrome (6714286824176).

The spelling of 1200143414155 in words is "one trillion, two hundred billion, one hundred forty-three million, four hundred fourteen thousand, one hundred fifty-five".

Divisors: 1 5 7 35 34289811833 171449059165 240028682831 1200143414155