Base | Representation |
---|---|
bin | 10001011101101110000… |
… | …111110011001110000011 |
3 | 11020201210001120022012112 |
4 | 101131232013303032003 |
5 | 124130343203223042 |
6 | 2315201022245535 |
7 | 152464446463046 |
oct | 21355607631603 |
9 | 4221701508175 |
10 | 1200143414147 |
11 | 422a83740287 |
12 | 1747197268ab |
13 | 8923321c052 |
14 | 421315bac5d |
15 | 213425b8982 |
hex | 1176e1f3383 |
1200143414147 has 2 divisors, whose sum is σ = 1200143414148. Its totient is φ = 1200143414146.
The previous prime is 1200143414011. The next prime is 1200143414209. The reversal of 1200143414147 is 7414143410021.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (7414143410021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1200143414147 - 238 = 925265507203 is a prime.
It is not a weakly prime, because it can be changed into another prime (1200143114147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600071707073 + 600071707074.
It is an arithmetic number, because the mean of its divisors is an integer number (600071707074).
Almost surely, 21200143414147 is an apocalyptic number.
1200143414147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200143414147 is an equidigital number, since it uses as much as digits as its factorization.
1200143414147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 32.
Adding to 1200143414147 its reverse (7414143410021), we get a palindrome (8614286824168).
The spelling of 1200143414147 in words is "one trillion, two hundred billion, one hundred forty-three million, four hundred fourteen thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •