Search a number
-
+
120015344041 = 314099465679
BaseRepresentation
bin110111111000101111…
…0001101000110101001
3102110210002001011120021
41233301132031012221
53431242412002131
6131045001200441
711446043410135
oct1576136150651
9373702034507
10120015344041
114699759534a
121b314a90121
13b41842a498
145b473bc3c5
1531c64d6e11
hex1bf178d1a9

120015344041 has 8 divisors (see below), whose sum is σ = 124189721600. Its totient is φ = 115859898720.

The previous prime is 120015344011. The next prime is 120015344063. The reversal of 120015344041 is 140443510021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120015344041 - 233 = 111425409449 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120015343997 and 120015344015.

It is not an unprimeable number, because it can be changed into a prime (120015344011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4720161 + ... + 4745518.

It is an arithmetic number, because the mean of its divisors is an integer number (15523715200).

Almost surely, 2120015344041 is an apocalyptic number.

It is an amenable number.

120015344041 is a deficient number, since it is larger than the sum of its proper divisors (4174377559).

120015344041 is an equidigital number, since it uses as much as digits as its factorization.

120015344041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9466119.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 120015344041 its reverse (140443510021), we get a palindrome (260458854062).

The spelling of 120015344041 in words is "one hundred twenty billion, fifteen million, three hundred forty-four thousand, forty-one".

Divisors: 1 31 409 12679 9465679 293436049 3871462711 120015344041