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12002122311 = 34000707437
BaseRepresentation
bin10110010110110000…
…11101101001000111
31010222110002222121120
423023120131221013
5144040020403221
65302543045023
7603265233144
oct131330355107
933873088546
1012002122311
1150a9981153
1223ab5a0773
13119372882a
1481c0113cb
154a3a3e5c6
hex2cb61da47

12002122311 has 4 divisors (see below), whose sum is σ = 16002829752. Its totient is φ = 8001414872.

The previous prime is 12002122309. The next prime is 12002122313. The reversal of 12002122311 is 11322120021.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12002122309) and next prime (12002122313).

It is a cyclic number.

It is not a de Polignac number, because 12002122311 - 21 = 12002122309 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12002122313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000353716 + ... + 2000353721.

It is an arithmetic number, because the mean of its divisors is an integer number (4000707438).

Almost surely, 212002122311 is an apocalyptic number.

12002122311 is a deficient number, since it is larger than the sum of its proper divisors (4000707441).

12002122311 is an equidigital number, since it uses as much as digits as its factorization.

12002122311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4000707440.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12002122311 its reverse (11322120021), we get a palindrome (23324242332).

The spelling of 12002122311 in words is "twelve billion, two million, one hundred twenty-two thousand, three hundred eleven".

Divisors: 1 3 4000707437 12002122311