Base | Representation |
---|---|
bin | 11011010010100010100010… |
… | …111101101100011010101101 |
3 | 120201221220221202212100211201 |
4 | 123102202202331230122231 |
5 | 111212412110322414013 |
6 | 1103133005114045501 |
7 | 34165152464000002 |
oct | 3322424275543255 |
9 | 521856852770751 |
10 | 120021300201133 |
11 | 35273825018621 |
12 | 11564b22719891 |
13 | 51c7c632acc96 |
14 | 218d0c1cc98a9 |
15 | dd20696013dd |
hex | 6d28a2f6c6ad |
120021300201133 has 4 divisors (see below), whose sum is σ = 124159965725340. Its totient is φ = 115882634676928.
The previous prime is 120021300201071. The next prime is 120021300201139. The reversal of 120021300201133 is 331102003120021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 72383392512649 + 47637907688484 = 8507843^2 + 6902022^2 .
It is a cyclic number.
It is not a de Polignac number, because 120021300201133 - 245 = 84836928112301 is a prime.
It is a super-2 number, since 2×1200213002011332 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120021300201133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120021300201139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2069332762060 + ... + 2069332762117.
It is an arithmetic number, because the mean of its divisors is an integer number (31039991431335).
Almost surely, 2120021300201133 is an apocalyptic number.
It is an amenable number.
120021300201133 is a deficient number, since it is larger than the sum of its proper divisors (4138665524207).
120021300201133 is an equidigital number, since it uses as much as digits as its factorization.
120021300201133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4138665524206.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 120021300201133 its reverse (331102003120021), we get a palindrome (451123303321154).
The spelling of 120021300201133 in words is "one hundred twenty trillion, twenty-one billion, three hundred million, two hundred one thousand, one hundred thirty-three".
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