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120021313120303 = 717145901874329
BaseRepresentation
bin11011010010100010100011…
…101110111110100000101111
3120201221220222200011201121111
4123102202203232332200233
5111212412122124322203
61103133010255012451
734165153011545140
oct3322424356764057
9521856880151544
10120021313120303
1135273831341a21
1211564b26b0a127
1351c7c65b8446a
14218d0c38cdac7
15dd206a80426d
hex6d28a3bbe82f

120021313120303 has 4 divisors (see below), whose sum is σ = 137167214994640. Its totient is φ = 102875411245968.

The previous prime is 120021313120253. The next prime is 120021313120327. The reversal of 120021313120303 is 303021313120021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120021313120303 - 29 = 120021313119791 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120021313120333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8572950937158 + ... + 8572950937171.

It is an arithmetic number, because the mean of its divisors is an integer number (34291803748660).

Almost surely, 2120021313120303 is an apocalyptic number.

120021313120303 is a deficient number, since it is larger than the sum of its proper divisors (17145901874337).

120021313120303 is an equidigital number, since it uses as much as digits as its factorization.

120021313120303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17145901874336.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 120021313120303 its reverse (303021313120021), we get a palindrome (423042626240324).

The spelling of 120021313120303 in words is "one hundred twenty trillion, twenty-one billion, three hundred thirteen million, one hundred twenty thousand, three hundred three".

Divisors: 1 7 17145901874329 120021313120303