1200213133001 has 4 divisors (see below), whose sum is σ = 1202507996112. Its totient is φ = 1197918269892.

The previous prime is 1200213132973. The next prime is 1200213133039. The reversal of 1200213133001 is 1003313120021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200213133001 - 2¹⁰ = 1200213131977 is a prime.

It is a super-2 number, since 2×1200213133001² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200213133081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1147430771 + ... + 1147431816.

It is an arithmetic number, because the mean of its divisors is an integer number (300626999028).

Almost surely, 2^{1200213133001} is an apocalyptic number.

It is an amenable number.

1200213133001 is a deficient number, since it is larger than the sum of its proper divisors (2294863111).

1200213133001 is an equidigital number, since it uses as much as digits as its factorization.

1200213133001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2294863110.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1200213133001 its reverse (1003313120021), we get a palindrome (2203526253022).

The spelling of 1200213133001 in words is "one trillion, two hundred billion, two hundred thirteen million, one hundred thirty-three thousand, one".