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1200213132973 is a prime number
BaseRepresentation
bin10001011101110010010…
…001110000011010101101
311020201221220202101110021
4101131302101300122231
5124131014030223343
62315211552442141
7152466254205661
oct21356221603255
94221856671407
101200213132973
1142300a02a048
12174738b49351
13892447bc8aa
144213a9688a1
152134878b0ed
hex117724706ad

1200213132973 has 2 divisors, whose sum is σ = 1200213132974. Its totient is φ = 1200213132972.

The previous prime is 1200213132949. The next prime is 1200213133039. The reversal of 1200213132973 is 3792313120021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 955072289284 + 245140843689 = 977278^2 + 495117^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200213132973 - 25 = 1200213132941 is a prime.

It is a super-5 number, since 5×12002131329735 (a number of 62 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200213138973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600106566486 + 600106566487.

It is an arithmetic number, because the mean of its divisors is an integer number (600106566487).

Almost surely, 21200213132973 is an apocalyptic number.

It is an amenable number.

1200213132973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200213132973 is an equidigital number, since it uses as much as digits as its factorization.

1200213132973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 34.

Adding to 1200213132973 its reverse (3792313120021), we get a palindrome (4992526252994).

The spelling of 1200213132973 in words is "one trillion, two hundred billion, two hundred thirteen million, one hundred thirty-two thousand, nine hundred seventy-three".