Base | Representation |
---|---|
bin | 10001011101110010010… |
… | …101001001100100011111 |
3 | 11020201221222102120120011 |
4 | 101131302111021210133 |
5 | 124131014242204211 |
6 | 2315212023504051 |
7 | 152466264602104 |
oct | 21356225114437 |
9 | 4221858376504 |
10 | 1200214022431 |
11 | 42300a587336 |
12 | 1747392b8027 |
13 | 89244a416b8 |
14 | 4213ab1aaab |
15 | 213488b4921 |
hex | 1177254991f |
1200214022431 has 4 divisors (see below), whose sum is σ = 1200242043000. Its totient is φ = 1200186001864.
The previous prime is 1200214022419. The next prime is 1200214022437. The reversal of 1200214022431 is 1342204120021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200214022431 is a prime.
It is a super-2 number, since 2×12002140224312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200214022437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13945936 + ... + 14031733.
It is an arithmetic number, because the mean of its divisors is an integer number (300060510750).
Almost surely, 21200214022431 is an apocalyptic number.
1200214022431 is a deficient number, since it is larger than the sum of its proper divisors (28020569).
1200214022431 is an equidigital number, since it uses as much as digits as its factorization.
1200214022431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28020568.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 1200214022431 its reverse (1342204120021), we get a palindrome (2542418142452).
The spelling of 1200214022431 in words is "one trillion, two hundred billion, two hundred fourteen million, twenty-two thousand, four hundred thirty-one".
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