12003101201213 has 4 divisors (see below), whose sum is σ = 12039364347168. Its totient is φ = 11966838055260.

The previous prime is 12003101201191. The next prime is 12003101201239. The reversal of 12003101201213 is 31210210130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12003101201213 - 2¹⁴ = 12003101184829 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003101201191 and 12003101201200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003101201513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18131572481 + ... + 18131573142.

It is an arithmetic number, because the mean of its divisors is an integer number (3009841086792).

Almost surely, 2^{12003101201213} is an apocalyptic number.

It is an amenable number.

12003101201213 is a deficient number, since it is larger than the sum of its proper divisors (36263145955).

12003101201213 is an equidigital number, since it uses as much as digits as its factorization.

12003101201213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36263145954.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12003101201213 its reverse (31210210130021), we get a palindrome (43213311331234).

The spelling of 12003101201213 in words is "twelve trillion, three billion, one hundred one million, two hundred one thousand, two hundred thirteen".