Base | Representation |
---|---|
bin | 11011010010101011101100… |
… | …010001110000110011001011 |
3 | 120201222212022010210121100221 |
4 | 123102223230101300303023 |
5 | 111213042213223231243 |
6 | 1103141311345210511 |
7 | 34165651024021630 |
oct | 3322535421606313 |
9 | 521885263717327 |
10 | 120031120133323 |
11 | 35277a04123a63 |
12 | 11566a03330a37 |
13 | 51c8b698a1749 |
14 | 218d774178187 |
15 | dd2441790bed |
hex | 6d2aec470ccb |
120031120133323 has 8 divisors (see below), whose sum is σ = 137178757218560. Its totient is φ = 102883566600360.
The previous prime is 120031120133317. The next prime is 120031120133339. The reversal of 120031120133323 is 323331021130021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 120031120133323 - 245 = 84846748044491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120031120113323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17778783 + ... + 23582776.
It is an arithmetic number, because the mean of its divisors is an integer number (17147344652320).
Almost surely, 2120031120133323 is an apocalyptic number.
120031120133323 is a deficient number, since it is larger than the sum of its proper divisors (17147637085237).
120031120133323 is an equidigital number, since it uses as much as digits as its factorization.
120031120133323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41776137.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 120031120133323 its reverse (323331021130021), we get a palindrome (443362141263344).
The spelling of 120031120133323 in words is "one hundred twenty trillion, thirty-one billion, one hundred twenty million, one hundred thirty-three thousand, three hundred twenty-three".
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