Base | Representation |
---|---|
bin | 1010111010101011000100… |
… | …1110100111000001101001 |
3 | 1120111111010111220012121000 |
4 | 2232222301032213001221 |
5 | 3033124333134201441 |
6 | 41310053055305213 |
7 | 2346124206531213 |
oct | 256526116470151 |
9 | 46444114805530 |
10 | 12003112022121 |
11 | 39085448a8110 |
12 | 141a349b1b209 |
13 | 690b723669ac |
14 | 2d6d4d0255b3 |
15 | 15c3662412b6 |
hex | aeab13a7069 |
12003112022121 has 16 divisors (see below), whose sum is σ = 19398968925120. Its totient is φ = 7274613346560.
The previous prime is 12003112022119. The next prime is 12003112022123. The reversal of 12003112022121 is 12122021130021.
12003112022121 is a `hidden beast` number, since 120 + 0 + 311 + 20 + 2 + 212 + 1 = 666.
12003112022121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (12003112022119) and next prime (12003112022123).
It is not a de Polignac number, because 12003112022121 - 21 = 12003112022119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12003112022094 and 12003112022103.
It is not an unprimeable number, because it can be changed into a prime (12003112022123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20207259000 + ... + 20207259593.
It is an arithmetic number, because the mean of its divisors is an integer number (1212435557820).
Almost surely, 212003112022121 is an apocalyptic number.
12003112022121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
12003112022121 is a deficient number, since it is larger than the sum of its proper divisors (7395856902999).
12003112022121 is a wasteful number, since it uses less digits than its factorization.
12003112022121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40414518613 (or 40414518607 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 12003112022121 its reverse (12122021130021), we get a palindrome (24125133152142).
The spelling of 12003112022121 in words is "twelve trillion, three billion, one hundred twelve million, twenty-two thousand, one hundred twenty-one".
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