12003121112133 has 4 divisors (see below), whose sum is σ = 16004161482848. Its totient is φ = 8002080741420.

The previous prime is 12003121112117. The next prime is 12003121112153. The reversal of 12003121112133 is 33121112130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12003121112133 - 2⁴ = 12003121112117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003121112153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000520185353 + ... + 2000520185358.

It is an arithmetic number, because the mean of its divisors is an integer number (4001040370712).

Almost surely, 2^{12003121112133} is an apocalyptic number.

It is an amenable number.

12003121112133 is a deficient number, since it is larger than the sum of its proper divisors (4001040370715).

12003121112133 is an equidigital number, since it uses as much as digits as its factorization.

12003121112133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4001040370714.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 12003121112133 its reverse (33121112130021), we get a palindrome (45124233242154).

The spelling of 12003121112133 in words is "twelve trillion, three billion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirty-three".