12003121241 has 4 divisors (see below), whose sum is σ = 12003896592. Its totient is φ = 12002345892.

The previous prime is 12003121211. The next prime is 12003121243. The reversal of 12003121241 is 14212130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14212130021 = 29 ⋅490073449.

It is a cyclic number.

It is not a de Polignac number, because 12003121241 - 2⁶ = 12003121177 is a prime.

It is a super-2 number, since 2×12003121241² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12003121243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363971 + ... + 395576.

It is an arithmetic number, because the mean of its divisors is an integer number (3000974148).

Almost surely, 2^12003121241 is an apocalyptic number.

It is an amenable number.

12003121241 is a deficient number, since it is larger than the sum of its proper divisors (775351).

12003121241 is an equidigital number, since it uses as much as digits as its factorization.

12003121241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 775350.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12003121241 its reverse (14212130021), we get a palindrome (26215251262).

The spelling of 12003121241 in words is "twelve billion, three million, one hundred twenty-one thousand, two hundred forty-one".