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120032001120103 = 449267331851047
BaseRepresentation
bin11011010010101100100000…
…110010011101011101100111
3120201222221120112112101000221
4123102230200302131131213
5111213101014241320403
61103141535015545211
734166011612211332
oct3322544062353547
9521887515471027
10120032001120103
113527831644a406
121156700a38b207
1351c8c7a26bbb7
14218d819185619
15dd2493cb3dbd
hex6d2b20c9d767

120032001120103 has 4 divisors (see below), whose sum is σ = 120299332971600. Its totient is φ = 119764669268608.

The previous prime is 120032001120091. The next prime is 120032001120113. The reversal of 120032001120103 is 301021100230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120032001120103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120032001120113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133665925075 + ... + 133665925972.

It is an arithmetic number, because the mean of its divisors is an integer number (30074833242900).

Almost surely, 2120032001120103 is an apocalyptic number.

120032001120103 is a deficient number, since it is larger than the sum of its proper divisors (267331851497).

120032001120103 is an equidigital number, since it uses as much as digits as its factorization.

120032001120103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267331851496.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 120032001120103 its reverse (301021100230021), we get a palindrome (421053101350124).

The spelling of 120032001120103 in words is "one hundred twenty trillion, thirty-two billion, one million, one hundred twenty thousand, one hundred three".

Divisors: 1 449 267331851047 120032001120103