12003200309 has 4 divisors (see below), whose sum is σ = 12012499200. Its totient is φ = 11993901420.

The previous prime is 12003200257. The next prime is 12003200351. The reversal of 12003200309 is 90300230021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 90300230021 = 25087 ⋅3599483.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003200309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003200359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4647509 + ... + 4650090.

It is an arithmetic number, because the mean of its divisors is an integer number (3003124800).

Almost surely, 2^12003200309 is an apocalyptic number.

It is an amenable number.

12003200309 is a deficient number, since it is larger than the sum of its proper divisors (9298891).

12003200309 is an equidigital number, since it uses as much as digits as its factorization.

12003200309 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9298890.

The product of its (nonzero) digits is 324, while the sum is 20.

The spelling of 12003200309 in words is "twelve billion, three million, two hundred thousand, three hundred nine".