12003200311 has 4 divisors (see below), whose sum is σ = 12417103800. Its totient is φ = 11589296824.

The previous prime is 12003200257. The next prime is 12003200351. The reversal of 12003200311 is 11300230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003200311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003200291 and 12003200300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003200351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206951701 + ... + 206951758.

It is an arithmetic number, because the mean of its divisors is an integer number (3104275950).

Almost surely, 2^12003200311 is an apocalyptic number.

12003200311 is a deficient number, since it is larger than the sum of its proper divisors (413903489).

12003200311 is an equidigital number, since it uses as much as digits as its factorization.

12003200311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 413903488.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 12003200311 its reverse (11300230021), we get a palindrome (23303430332).

The spelling of 12003200311 in words is "twelve billion, three million, two hundred thousand, three hundred eleven".