1200320112023 has 4 divisors (see below), whose sum is σ = 1200323411280. Its totient is φ = 1200316812768.

The previous prime is 1200320112001. The next prime is 1200320112067. The reversal of 1200320112023 is 3202110230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1200320112023 - 2¹² = 1200320107927 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200320111992 and 1200320112010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200320112223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025090 + ... + 1857807.

It is an arithmetic number, because the mean of its divisors is an integer number (300080852820).

Almost surely, 2^{1200320112023} is an apocalyptic number.

1200320112023 is a deficient number, since it is larger than the sum of its proper divisors (3299257).

1200320112023 is an equidigital number, since it uses as much as digits as its factorization.

1200320112023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3299256.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1200320112023 its reverse (3202110230021), we get a palindrome (4402430342044).

The spelling of 1200320112023 in words is "one trillion, two hundred billion, three hundred twenty million, one hundred twelve thousand, twenty-three".