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12003201211 = 14398341349
BaseRepresentation
bin10110010110111001…
…00101000010111011
31010222112010210120211
423023130211002323
5144040304414321
65303022131551
7603310345501
oct131334450273
933875123524
1012003201211
1150aa548801
1223aba20bb7
131193a15931
1481c212671
154a3ba40e1
hex2cb7250bb

12003201211 has 4 divisors (see below), whose sum is σ = 12011544000. Its totient is φ = 11994858424.

The previous prime is 12003201193. The next prime is 12003201229. The reversal of 12003201211 is 11210230021.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12003201193) and next prime (12003201229).

It is a cyclic number.

It is not a de Polignac number, because 12003201211 - 217 = 12003070139 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003201191 and 12003201200.

It is not an unprimeable number, because it can be changed into a prime (12003201011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4169236 + ... + 4172113.

It is an arithmetic number, because the mean of its divisors is an integer number (3002886000).

Almost surely, 212003201211 is an apocalyptic number.

12003201211 is a deficient number, since it is larger than the sum of its proper divisors (8342789).

12003201211 is an equidigital number, since it uses as much as digits as its factorization.

12003201211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8342788.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12003201211 its reverse (11210230021), we get a palindrome (23213431232).

The spelling of 12003201211 in words is "twelve billion, three million, two hundred one thousand, two hundred eleven".

Divisors: 1 1439 8341349 12003201211