12003222113031 has 4 divisors (see below), whose sum is σ = 16004296150712. Its totient is φ = 8002148075352.

The previous prime is 12003222112993. The next prime is 12003222113033. The reversal of 12003222113031 is 13031122230021.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-12003222113031 is a prime.

It is a super-2 number, since 2×12003222113031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003222112989 and 12003222113007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003222113033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000537018836 + ... + 2000537018841.

It is an arithmetic number, because the mean of its divisors is an integer number (4001074037678).

Almost surely, 2^{12003222113031} is an apocalyptic number.

12003222113031 is a deficient number, since it is larger than the sum of its proper divisors (4001074037681).

12003222113031 is an equidigital number, since it uses as much as digits as its factorization.

12003222113031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4001074037680.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12003222113031 its reverse (13031122230021), we get a palindrome (25034344343052).

The spelling of 12003222113031 in words is "twelve trillion, three billion, two hundred twenty-two million, one hundred thirteen thousand, thirty-one".