1200323230133 has 4 divisors (see below), whose sum is σ = 1200330282240. Its totient is φ = 1200316178028.

The previous prime is 1200323230129. The next prime is 1200323230153. The reversal of 1200323230133 is 3310323230021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200323230133 - 2² = 1200323230129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200323230099 and 1200323230108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200323230103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3264263 + ... + 3613316.

It is an arithmetic number, because the mean of its divisors is an integer number (300082570560).

Almost surely, 2^{1200323230133} is an apocalyptic number.

It is an amenable number.

1200323230133 is a deficient number, since it is larger than the sum of its proper divisors (7052107).

1200323230133 is an equidigital number, since it uses as much as digits as its factorization.

1200323230133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7052106.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 1200323230133 its reverse (3310323230021), we get a palindrome (4510646460154).

The spelling of 1200323230133 in words is "one trillion, two hundred billion, three hundred twenty-three million, two hundred thirty thousand, one hundred thirty-three".