12003333141 has 4 divisors (see below), whose sum is σ = 16004444192. Its totient is φ = 8002222092.

The previous prime is 12003333113. The next prime is 12003333151. The reversal of 12003333141 is 14133330021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12003333141 - 2⁶ = 12003333077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003333101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000555521 + ... + 2000555526.

It is an arithmetic number, because the mean of its divisors is an integer number (4001111048).

Almost surely, 2^12003333141 is an apocalyptic number.

It is an amenable number.

12003333141 is a deficient number, since it is larger than the sum of its proper divisors (4001111051).

12003333141 is an equidigital number, since it uses as much as digits as its factorization.

12003333141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4001111050.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 12003333141 its reverse (14133330021), we get a palindrome (26136663162).

The spelling of 12003333141 in words is "twelve billion, three million, three hundred thirty-three thousand, one hundred forty-one".