12003656403433 has 4 divisors (see below), whose sum is σ = 12037661096148. Its totient is φ = 11969651710720.

The previous prime is 12003656403413. The next prime is 12003656403461. The reversal of 12003656403433 is 33430465630021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1930732482064 + 10072923921369 = 1389508^2 + 3173787^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003656403433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12003656403413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17002345828 + ... + 17002346533.

It is an arithmetic number, because the mean of its divisors is an integer number (3009415274037).

Almost surely, 2^{12003656403433} is an apocalyptic number.

It is an amenable number.

12003656403433 is a deficient number, since it is larger than the sum of its proper divisors (34004692715).

12003656403433 is an equidigital number, since it uses as much as digits as its factorization.

12003656403433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34004692714.

The product of its (nonzero) digits is 466560, while the sum is 40.

The spelling of 12003656403433 in words is "twelve trillion, three billion, six hundred fifty-six million, four hundred three thousand, four hundred thirty-three".