12003943 has 4 divisors (see below), whose sum is σ = 13718800. Its totient is φ = 10289088.

The previous prime is 12003911. The next prime is 12003961. The reversal of 12003943 is 34930021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12003943 - 2⁵ = 12003911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003743) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857418 + ... + 857431.

It is an arithmetic number, because the mean of its divisors is an integer number (3429700).

Almost surely, 2^12003943 is an apocalyptic number.

12003943 is a deficient number, since it is larger than the sum of its proper divisors (1714857).

12003943 is an equidigital number, since it uses as much as digits as its factorization.

12003943 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1714856.

The product of its (nonzero) digits is 648, while the sum is 22.

The square root of 12003943 is about 3464.6706914222. The cubic root of 12003943 is about 228.9679213661.

Adding to 12003943 its reverse (34930021), we get a palindrome (46933964).

The spelling of 12003943 in words is "twelve million, three thousand, nine hundred forty-three".