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120040123143 = 367597214543
BaseRepresentation
bin110111111001011110…
…0101110101100000111
3102110211210200002002210
41233302330232230013
53431320232420033
6131051244234503
711446464132333
oct1576274565407
9373753602083
10120040123143
11469aa57a246
121b32123ba33
13b4205c4c85
145b4a7cc7c3
1531c877dd63
hex1bf2f2eb07

120040123143 has 8 divisors (see below), whose sum is σ = 162442355968. Its totient is φ = 78832319544.

The previous prime is 120040123057. The next prime is 120040123207. The reversal of 120040123143 is 341321040021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 120040123143 - 213 = 120040114951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120040123543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 298607071 + ... + 298607472.

It is an arithmetic number, because the mean of its divisors is an integer number (20305294496).

Almost surely, 2120040123143 is an apocalyptic number.

120040123143 is a deficient number, since it is larger than the sum of its proper divisors (42402232825).

120040123143 is an equidigital number, since it uses as much as digits as its factorization.

120040123143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 597214613.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 120040123143 its reverse (341321040021), we get a palindrome (461361163164).

The spelling of 120040123143 in words is "one hundred twenty billion, forty million, one hundred twenty-three thousand, one hundred forty-three".

Divisors: 1 3 67 201 597214543 1791643629 40013374381 120040123143