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12004051153 = 71169071143
BaseRepresentation
bin10110010110111111…
…10100100011010001
31010222120201222111011
423023133310203101
5144041014114103
65303052250521
7603320515453
oct131337644321
933876658434
1012004051153
1150aaa79336
1223b0170a41
131193c52763
1481c3942d3
154a3cc0d6d
hex2cb7f48d1

12004051153 has 4 divisors (see below), whose sum is σ = 12173122368. Its totient is φ = 11834979940.

The previous prime is 12004051151. The next prime is 12004051159. The reversal of 12004051153 is 35115040021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12004051153 - 21 = 12004051151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12004051151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84535501 + ... + 84535642.

It is an arithmetic number, because the mean of its divisors is an integer number (3043280592).

Almost surely, 212004051153 is an apocalyptic number.

It is an amenable number.

12004051153 is a deficient number, since it is larger than the sum of its proper divisors (169071215).

12004051153 is an equidigital number, since it uses as much as digits as its factorization.

12004051153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169071214.

The product of its (nonzero) digits is 600, while the sum is 22.

Adding to 12004051153 its reverse (35115040021), we get a palindrome (47119091174).

The spelling of 12004051153 in words is "twelve billion, four million, fifty-one thousand, one hundred fifty-three".

Divisors: 1 71 169071143 12004051153