Base | Representation |
---|---|
bin | 1010111010101110110110… |
… | …0111000001100010110011 |
3 | 1120111120202010002121200000 |
4 | 2232223231213001202303 |
5 | 3033133422003231110 |
6 | 41310341404201043 |
7 | 2346161260263252 |
oct | 256535547014263 |
9 | 46446663077600 |
10 | 12004125055155 |
11 | 3908a147128a2 |
12 | 141a591239183 |
13 | 690ca41b811c |
14 | 2d70077a6799 |
15 | 15c3c51491c0 |
hex | aeaed9c18b3 |
12004125055155 has 24 divisors (see below), whose sum is σ = 21577785286512. Its totient is φ = 6402200028768.
The previous prime is 12004125055147. The next prime is 12004125055189. The reversal of 12004125055155 is 55155052140021.
12004125055155 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 4 + 1 + 2 + 50 + 551 + 55 = 666.
It is not a de Polignac number, because 12004125055155 - 23 = 12004125055147 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4939967944 + ... + 4939970373.
It is an arithmetic number, because the mean of its divisors is an integer number (899074386938).
Almost surely, 212004125055155 is an apocalyptic number.
12004125055155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12004125055155 is a deficient number, since it is larger than the sum of its proper divisors (9573660231357).
12004125055155 is an frugal number, since it uses more digits than its factorization.
12004125055155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9879938337 (or 9879938325 counting only the distinct ones).
The product of its (nonzero) digits is 50000, while the sum is 36.
Adding to 12004125055155 its reverse (55155052140021), we get a palindrome (67159177195176).
The spelling of 12004125055155 in words is "twelve trillion, four billion, one hundred twenty-five million, fifty-five thousand, one hundred fifty-five".
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