1200413020133 has 4 divisors (see below), whose sum is σ = 1206632776908. Its totient is φ = 1194193263360.

The previous prime is 1200413020117. The next prime is 1200413020153. The reversal of 1200413020133 is 3310203140021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 572771971489 + 627641048644 = 756817^2 + 792238^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200413020133 - 2⁴ = 1200413020117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200413020153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3109878098 + ... + 3109878483.

It is an arithmetic number, because the mean of its divisors is an integer number (301658194227).

Almost surely, 2^{1200413020133} is an apocalyptic number.

It is an amenable number.

1200413020133 is a deficient number, since it is larger than the sum of its proper divisors (6219756775).

1200413020133 is an equidigital number, since it uses as much as digits as its factorization.

1200413020133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6219756774.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1200413020133 its reverse (3310203140021), we get a palindrome (4510616160154).

The spelling of 1200413020133 in words is "one trillion, two hundred billion, four hundred thirteen million, twenty thousand, one hundred thirty-three".