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12004143142103 = 73709462355781
BaseRepresentation
bin1010111010101110111010…
…1100000001010011010111
31120111120210101010112021222
42232223232230001103113
53033133441121021403
641310343252000555
72346161600104010
oct256535654012327
946446711115258
1012004143142103
113908a23946892
12141a59730015b
13690ca7b7b868
142d7009d54007
1515c3c6a1d338
hexaeaeeb014d7

12004143142103 has 8 divisors (see below), whose sum is σ = 13722719609760. Its totient is φ = 10286491393440.

The previous prime is 12004143142099. The next prime is 12004143142169. The reversal of 12004143142103 is 30124134140021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12004143142103 - 22 = 12004143142099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12004143147103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 231151928 + ... + 231203853.

It is an arithmetic number, because the mean of its divisors is an integer number (1715339951220).

Almost surely, 212004143142103 is an apocalyptic number.

12004143142103 is a deficient number, since it is larger than the sum of its proper divisors (1718576467657).

12004143142103 is an equidigital number, since it uses as much as digits as its factorization.

12004143142103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462359497.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 12004143142103 its reverse (30124134140021), we get a palindrome (42128277282124).

The spelling of 12004143142103 in words is "twelve trillion, four billion, one hundred forty-three million, one hundred forty-two thousand, one hundred three".

Divisors: 1 7 3709 25963 462355781 3236490467 1714877591729 12004143142103