Base | Representation |
---|---|
bin | 10001011101111110110… |
… | …111011100101010011001 |
3 | 11020202111122011211012020 |
4 | 101131332313130222121 |
5 | 124131432112340441 |
6 | 2315244535405053 |
7 | 152504430351156 |
oct | 21357667345231 |
9 | 4222448154166 |
10 | 1200424340121 |
11 | 423108277106 |
12 | 174797823789 |
13 | 8927949c036 |
14 | 4215aa2722d |
15 | 2135c0aae66 |
hex | 1177eddca99 |
1200424340121 has 4 divisors (see below), whose sum is σ = 1600565786832. Its totient is φ = 800282893412.
The previous prime is 1200424340107. The next prime is 1200424340153. The reversal of 1200424340121 is 1210434240021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1200424340121 - 26 = 1200424340057 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200424340091 and 1200424340100.
It is not an unprimeable number, because it can be changed into a prime (1200424347121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200070723351 + ... + 200070723356.
It is an arithmetic number, because the mean of its divisors is an integer number (400141446708).
Almost surely, 21200424340121 is an apocalyptic number.
It is an amenable number.
1200424340121 is a deficient number, since it is larger than the sum of its proper divisors (400141446711).
1200424340121 is an equidigital number, since it uses as much as digits as its factorization.
1200424340121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 400141446710.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1200424340121 its reverse (1210434240021), we get a palindrome (2410858580142).
The spelling of 1200424340121 in words is "one trillion, two hundred billion, four hundred twenty-four million, three hundred forty thousand, one hundred twenty-one".
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