Base | Representation |
---|---|
bin | 10110010111000010… |
… | …01111101000111011 |
3 | 1010222121102221021121 |
4 | 23023201033220323 |
5 | 144041113034001 |
6 | 5303104250111 |
7 | 603323631301 |
oct | 131341175073 |
9 | 33877387247 |
10 | 12004424251 |
11 | 5100203686 |
12 | 23b0310937 |
13 | 1194053521 |
14 | 81c450271 |
15 | 4a3d466a1 |
hex | 2cb84fa3b |
12004424251 has 16 divisors (see below), whose sum is σ = 13052670048. Its totient is φ = 10996070400.
The previous prime is 12004424231. The next prime is 12004424273. The reversal of 12004424251 is 15242440021.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12004424251 is a prime.
It is a super-2 number, since 2×120044242512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12004424231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 176191 + ... + 234631.
It is an arithmetic number, because the mean of its divisors is an integer number (815791878).
Almost surely, 212004424251 is an apocalyptic number.
12004424251 is a deficient number, since it is larger than the sum of its proper divisors (1048245797).
12004424251 is a wasteful number, since it uses less digits than its factorization.
12004424251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58782.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 12004424251 its reverse (15242440021), we get a palindrome (27246864272).
The spelling of 12004424251 in words is "twelve billion, four million, four hundred twenty-four thousand, two hundred fifty-one".
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