12004444240313 has 4 divisors (see below), whose sum is σ = 13719364846080. Its totient is φ = 10289523634548.

The previous prime is 12004444240309. The next prime is 12004444240337. The reversal of 12004444240313 is 31304244440021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12004444240313 - 2² = 12004444240309 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12004444240313.

It is not an unprimeable number, because it can be changed into a prime (12004444240013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857460302873 + ... + 857460302886.

It is an arithmetic number, because the mean of its divisors is an integer number (3429841211520).

Almost surely, 2^{12004444240313} is an apocalyptic number.

It is an amenable number.

12004444240313 is a deficient number, since it is larger than the sum of its proper divisors (1714920605767).

12004444240313 is an equidigital number, since it uses as much as digits as its factorization.

12004444240313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1714920605766.

The product of its (nonzero) digits is 36864, while the sum is 32.

Adding to 12004444240313 its reverse (31304244440021), we get a palindrome (43308688680334).

The spelling of 12004444240313 in words is "twelve trillion, four billion, four hundred forty-four million, two hundred forty thousand, three hundred thirteen".