Base | Representation |
---|---|
bin | 11011010011000000001101… |
… | …000000001010101100011010 |
3 | 120202001222011000121020011211 |
4 | 123103000031000022230122 |
5 | 111213422314331133102 |
6 | 1103155353013213334 |
7 | 34200360552604336 |
oct | 3323001500125432 |
9 | 522058130536154 |
10 | 120053144005402 |
11 | 35286286015033 |
12 | 1156b12b03124a |
13 | 51cac6966140a |
14 | 21908631707c6 |
15 | dd2cd00377d7 |
hex | 6d300d00ab1a |
120053144005402 has 4 divisors (see below), whose sum is σ = 180079716008106. Its totient is φ = 60026572002700.
The previous prime is 120053144005391. The next prime is 120053144005411. The reversal of 120053144005402 is 204500441350021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 104598503930281 + 15454640075121 = 10227341^2 + 3931239^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30013286001349 + ... + 30013286001352.
Almost surely, 2120053144005402 is an apocalyptic number.
120053144005402 is a deficient number, since it is larger than the sum of its proper divisors (60026572002704).
120053144005402 is an equidigital number, since it uses as much as digits as its factorization.
120053144005402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60026572002703.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 120053144005402 its reverse (204500441350021), we get a palindrome (324553585355423).
The spelling of 120053144005402 in words is "one hundred twenty trillion, fifty-three billion, one hundred forty-four million, five thousand, four hundred two".
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