Base | Representation |
---|---|
bin | 10001011110001000011… |
… | …001010110001011100101 |
3 | 11020202220210000122002120 |
4 | 101132020121112023211 |
5 | 124132244030041123 |
6 | 2315312450300153 |
7 | 152511411334323 |
oct | 21361031261345 |
9 | 4222823018076 |
10 | 1200584221413 |
11 | 42318a548305 |
12 | 174821287659 |
13 | 892a364a755 |
14 | 42173d64d13 |
15 | 2136b13d2e3 |
hex | 117886562e5 |
1200584221413 has 4 divisors (see below), whose sum is σ = 1600778961888. Its totient is φ = 800389480940.
The previous prime is 1200584221357. The next prime is 1200584221519. The reversal of 1200584221413 is 3141224850021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1200584221413 - 212 = 1200584217317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200584225413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200097370233 + ... + 200097370238.
It is an arithmetic number, because the mean of its divisors is an integer number (400194740472).
Almost surely, 21200584221413 is an apocalyptic number.
It is an amenable number.
1200584221413 is a deficient number, since it is larger than the sum of its proper divisors (400194740475).
1200584221413 is an equidigital number, since it uses as much as digits as its factorization.
1200584221413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 400194740474.
The product of its (nonzero) digits is 15360, while the sum is 33.
The spelling of 1200584221413 in words is "one trillion, two hundred billion, five hundred eighty-four million, two hundred twenty-one thousand, four hundred thirteen".
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