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12010112013 = 34003370671
BaseRepresentation
bin10110010111101101…
…11100010000001101
31011000000010220102110
423023312330100031
5144044042041023
65303430214233
7603423160554
oct131366742015
934000126373
1012010112013
115103438a09
1223b21b4379
131195295373
1481d0d0d9b
154a45bba93
hex2cbdbc40d

12010112013 has 4 divisors (see below), whose sum is σ = 16013482688. Its totient is φ = 8006741340.

The previous prime is 12010111969. The next prime is 12010112041. The reversal of 12010112013 is 31021101021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12010112013 - 221 = 12008014861 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12010112013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12010112713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001685333 + ... + 2001685338.

It is an arithmetic number, because the mean of its divisors is an integer number (4003370672).

Almost surely, 212010112013 is an apocalyptic number.

It is an amenable number.

12010112013 is a deficient number, since it is larger than the sum of its proper divisors (4003370675).

12010112013 is an equidigital number, since it uses as much as digits as its factorization.

12010112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4003370674.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 12010112013 its reverse (31021101021), we get a palindrome (43031213034).

The spelling of 12010112013 in words is "twelve billion, ten million, one hundred twelve thousand, thirteen".

Divisors: 1 3 4003370671 12010112013