1201030202013 has 4 divisors (see below), whose sum is σ = 1601373602688. Its totient is φ = 800686801340.

The previous prime is 1201030202003. The next prime is 1201030202027. The reversal of 1201030202013 is 3102020301021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201030202013 - 2⁸ = 1201030201757 is a prime.

It is a super-2 number, since 2×1201030202013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1201030201983 and 1201030202001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201030202003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200171700333 + ... + 200171700338.

It is an arithmetic number, because the mean of its divisors is an integer number (400343400672).

Almost surely, 2^{1201030202013} is an apocalyptic number.

It is an amenable number.

1201030202013 is a deficient number, since it is larger than the sum of its proper divisors (400343400675).

1201030202013 is an equidigital number, since it uses as much as digits as its factorization.

1201030202013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400343400674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1201030202013 its reverse (3102020301021), we get a palindrome (4303050503034).

The spelling of 1201030202013 in words is "one trillion, two hundred one billion, thirty million, two hundred two thousand, thirteen".