120110002013 has 4 divisors (see below), whose sum is σ = 120369419328. Its totient is φ = 119850584700.

The previous prime is 120110001959. The next prime is 120110002037. The reversal of 120110002013 is 310200011021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120110002013 is a prime.

It is a super-3 number, since 3×120110002013³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120110001985 and 120110002003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120110007013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129707963 + ... + 129708888.

It is an arithmetic number, because the mean of its divisors is an integer number (30092354832).

Almost surely, 2^120110002013 is an apocalyptic number.

It is an amenable number.

120110002013 is a deficient number, since it is larger than the sum of its proper divisors (259417315).

120110002013 is an equidigital number, since it uses as much as digits as its factorization.

120110002013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259417314.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 120110002013 its reverse (310200011021), we get a palindrome (430310013034).

The spelling of 120110002013 in words is "one hundred twenty billion, one hundred ten million, two thousand, thirteen".